LlListSort
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Return value notes
Specification
The sort order is affected by type. For strings and keys, it is case sensitive and sorts by Unicode character code.
llListSort(["a", "á", "B", "C", "d", "e"], 1, TRUE) // returns ["B", "C", "a", "d", "e", "á"]For ascending sort, each type is sorted individually and then feathered to have the same order of types.
llListSort([1, "C", 3, "A", 2, "B"], 1, TRUE) // returns [1, "A", 2, "B", 3, "C"]
llListSort([1, 3, 2, "C", "A", "B"], 1, TRUE) // returns [1, 2, 3, "A", "B", "C"]
llListSort([1, "C", 3, "A", 2, "B"], 2, TRUE) // returns [1, "C", 2, "B", 3, "A"]
llListSort(["2ae", "ah5", "1ag", "aa6", "3ac", "ad7", "ab8", "4af", "ai9"], 1, TRUE);
// returns ["1ag", "2ae" ,"3ac" ,"4af" ,"aa6" ,"ab8" ,"ad7" ,"ah5" ,"ai9"]As a reminder, although floats and integers are both numeric and comparable, they too are treated separately.
llListSort([1, 3, 5, 2.0, 4.0, 6.0], 1, TRUE) // returns the list unchangedCaveats
- It uses an unoptimized selection sort algorithm, which is an algorithm with a Big O of N². A JIRA issue exists to improve this function, SVC-2988.
- Originally the wiki stated that non-zero values for the "ascending" parameter would produce an ascending sort. That was incorrect. For this function, the value must be exactly 1 (or TRUE) for an ascending sort.
- Vectors are sorted by magnitude. SVC-5643
- Rotations are not sorted. An ascending sort will simply leave any rotations unchanged, and a descending sort will reverse their order.
- For special float values: having NaNs in a list can confuse the sort order, as they are uncomparable. Negative zeroes are retained, but their positions with regard to ordinary zeroes depend on the list. Infinities behave as expected.
- For descending sort, if there are mixed types, the final order is deterministic (the same input will always produce the same output) but it can be completely useless.
If there are no mixed types, however, the descending sort works just fine.llListSort([2, "B", "C", 3, 1, "A"], 1, FALSE) // returns ["A", 3, 1, "C", "B", 2] - When the stride is greater than 1, if the list length is not a multiple of the stride, the list will be returned unchanged.
- When strings contain numbers, the numbers are still sorted left-to-right like any other character, which may not necessarily match numeric order:
To sort them in numeric order, numbers in strings can be padded with zeros:llListSort(["127", "3", "25"], 1, TRUE) // returns ["127", "25", "3"] because the 1 in 127 is before the 2 in 25 which is before the 3llListSort(["127", "003", "025"], 1, TRUE) // returns ["003", "025", "127"]- This order differs from the order of items in a prim's inventory, which is "natural order" (e.g "New Script 2" is sorted before "New Script 11").
Examples
list numbers = [3, "three", 2, "two", 1, "one"];
default
{
state_entry()
{
llOwnerSay(llDumpList2String(numbers, ","));
// Object: 3,three,2,two,1,one
numbers = llListSort(numbers, 2, TRUE);
llOwnerSay(llDumpList2String(numbers, ","));
// Object: 1,one,2,two,3,three
}
}Video Tutorial
KBvideo:
{{KBvideo|BNIUHnpeUQs|640|385|type=youtube}}Notes
Data Types
llListSort really only works on items of the same type. It will work on lists that hold diverse data types -- to be clear, it won't blow up your script -- but the results returned are usually meaningless.
list mylist = ["brown", <0.000000, 0.000000, 0.000000>, "house", 17.005, 100, "cat", <3.000000, 3.000000, 3.000000>, 39];
list tmplist = llListSort(mylist, 1, TRUE);
llSay(0, llList2CSV(tmplist));This returns in chat:
brown, <0.000000, 0.000000, 0.000000>, cat, 17.004999, 39, house, <3.000000, 3.000000, 3.000000>, 100
The same ordered in descending order returns even more meaningless results:
list mylist = ["brown", <0.000000, 0.000000, 0.000000>, "house", 17.005, 100, "cat", <3.000000, 3.000000, 3.000000>, 39];
list tmplist = llListSort(mylist, 1, FALSE);
llSay(0, llList2CSV(tmplist));returns in chat:
39, <3.000000, 3.000000, 3.000000>, cat, 100, 17.004999, house, <0.000000, 0.000000, 0.000000>, brown
Utilizing the Results
It's important to note that the source list that you are sorting will remain unchanged. Instead, a new, sorted list will be produced. So, it's important that you capture this with a variable (unless you are acting directly on the results.)
llListSort(myList, 1, TRUE); // You've wasted cpu time; you didn't capture the results
list newlist = llListSort(myList, 1, TRUE);// Okay. You've captured the results.
llSay(0,llList2CSV(llListSort(myList, 1, TRUE))); // No need to capture, using the results right away.Stride parameter
Most times, you will want to set "integer stride" to 1 (0 also works) to tell it to sort each item in the list on its own basis. (If you are working with a strided list, though, see the special section below on sorting strides.)
Sort Order
Setting the parameter "integer ascending" to TRUE returns a sorted list that is in ascending order.
For example: ["Apples", "Bananas", "Oranges"]
Setting the parameter "integer ascending" to FALSE returns a sorted list that is in descending order.
For example: ["Oranges", "Bananas", "Apples"]
Sorting Strided Lists
If you have a strided list, in which you are keeping related pieces of data together in chunks, letting each list element sort on its own basis would be disastrous.
list demographics = ["John Adams", "male", "2007-06-22", "Shirley Bassey", "female", "2005-11-02", "Matt Damon", "male", "2008-05-19"];Bad Example
list tmplist_1 = llListSort(demographics, 1, TRUE);
//tmplist_1 == ["2005-11-02", "2007-06-22", "2008-05-19", "John Adams", "Matt Damon", "Shirley Bassey", "female", "male", "male"]
//The strides have been destroyed, the sorted data is now uselessGood Example
Instead, because you have the data grouped (aka "strided") in sets of 3, you need to do this:
list tmplist_2 = llListSort(demographics, 3, TRUE);
//templist_2 = ["John Adams", "male", "2007-06-22", "Matt Damon", "male", "2008-05-19", "Shirley Bassey", "female", "2005-11-02"]When storing data in strided lists, it's often worth it down the road to take a moment at the outset to think about how you are most likely to want to sort them, if ever the need arose. Remember, you can only sort on the first element in each group of elements. If you think you're mostly likely to want to sort on gender (to use the above list example), you should make gender the first element in the data grouping.
See also: functions
Shared wiki helpers
The original page also injects shared parameter notes, caveats or issue information through these helpers. Their conditional MediaWiki logic is not reproduced here; inspect the preserved helper source for additional material.
Original shared helper source (conditional wiki logic is not evaluated)
{{Issues|SVC-2988|Convert [[llListSort]]() to use faster sorting methods!|type=nf}}Original shared helper source (conditional wiki logic is not evaluated)
{{Issues|SVC-5146|'''llSortedListFindList'''() - improved [[llListFindList]]() for known to be sorted lists|type=nf}}Original shared helper source (conditional wiki logic is not evaluated)
{{LSL Injection Test}}{{#if:
{{#vardefine:header_footnote|This function supports [[List#Strided_lists|Strided Lists]].}}
{{#vardefine:p_{{{1|none}}}_hover|number of entries per stride, if less than 1 it is assumed to be 1}}
{{#vardefine:p_{{{1|none}}}_desc|number of entries per stride, if less than 1 it is assumed to be 1}}
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</noinclude>Original wiki source
Some wiki templates and tables need their original context. View this article on the Second Life Wiki. Technical wording and examples are retained from the source; historical guidance may differ from current behavior.